Question
$\frac{\text{x}-3}{5}-2=-1$

Answer

$\frac{\text{x}-3}{5}-2=-1$
Adding 2 to both sides, we get
$\frac{\text{x}-3}{5}-2+2=-1+2$
$\frac{\text{x}-3}{5}=1$
Multiplying both sides by 5, we get
$\frac{\text{x}-3}{5}\times5=1\times5$
$\text{x}-3=5$
Adding 3 to both sides, we get
x - 3 + 3 = 5 + 3
x = 8
Verification:
Substituting x = 8 in L.H.S., we get
$=\frac{8-3}{5}-2=\frac{5}{5}-2=1-2=-1=\text{R.H.S.}$
Hence, verified.

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