MCQ
The $71^{st}$ electron of an element $X$ with an atomic number of $71$ enters into the orbital:
- A$6p$
- B$4f$
- ✓$5d$
- D$6s$
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[Assume : No cyano complex is formed; $K _{ sp }( AgCN )$ $=2.2 \times 10^{-16}$ and $\left. K _{ a }( HCN )=6.2 \times 10^{-10}\right]$
$\mathrm{H}_2(\mathrm{~g})+\mathrm{I}_2(\mathrm{~g}) \rightleftharpoons 2 \mathrm{HI}(\mathrm{g})$, the $\mathrm{K}_{\mathrm{p}}$ for the process is $\mathrm{x} \times 10^{-1} \cdot \mathrm{x}=$ $\qquad$
[Given : $\mathrm{R}=0.082 \mathrm{~L} \mathrm{~atm} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}$ ]