MCQ
At $-20^{\circ} \mathrm{C}$ and $1 \mathrm{~atm}$ pressure, a cylinder is filled with equal number of $\mathrm{H}_2 . \mathrm{I}_2$ and $\mathrm{HI}$ molecules for the reaction

$\mathrm{H}_2(\mathrm{~g})+\mathrm{I}_2(\mathrm{~g}) \rightleftharpoons 2 \mathrm{HI}(\mathrm{g})$, the $\mathrm{K}_{\mathrm{p}}$ for the process is $\mathrm{x} \times 10^{-1} \cdot \mathrm{x}=$ $\qquad$

[Given : $\mathrm{R}=0.082 \mathrm{~L} \mathrm{~atm} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}$ ]

  • A
    $2$
  • B
    $1$
  • $10$
  • D
    $0.01$

Answer

Correct option: C.
$10$
c
$\Delta \mathrm{n}_{\mathrm{g}}=0  \mathrm{~K}_{\mathrm{p}}=\frac{\left(\mathrm{n}_{\mathrm{HI}}\right)^2}{\mathrm{n}_{\mathrm{H}_2} \mathrm{n}_{\mathrm{I}_2}}\left(\frac{\mathrm{P}_{\mathrm{T}}}{\mathrm{n}_{\mathrm{T}}}\right)^{\Delta \mathrm{ng}_{\mathrm{g}}}$

$\mathrm{n}_{\mathrm{HI}}=\mathrm{n}_{\mathrm{H}_2}=\mathrm{n}_{\mathrm{I}_2}  \text { so } \mathrm{K}_{\mathrm{P}}=1$

$1=\mathrm{x} \times 10^{-1}  \mathrm{x}=10$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free