MCQ
The $8^{\text {th }}$ term of the A.P. $12,8,4,0, \ldots$ is:
  • -16
  • B
    -12
  • C
    -20
  • D
    -4

Answer

Correct option: A.
-16
(a) -16
Explanation:
In the given A.P.,
$a=12$ and $d=8-12=-4$
$\therefore 8^{\text {th }}$ term $=t_8=a+(8-1) d$
$\begin{array}{l}=12+7 \times(-4) \\ =-16 .\end{array}$

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