ICSE BoardEnglish MediumSTD 10MathematicsArithmetic Progression1 Mark
MCQ
The $8^{\text {th }}$ term of the A.P. $12,8,4,0, \ldots$ is:
✓
-16
B
-12
C
-20
D
-4
✓
Answer
Correct option: A.
-16
(a) -16 Explanation: In the given A.P., $a=12$ and $d=8-12=-4$ $\therefore 8^{\text {th }}$ term $=t_8=a+(8-1) d$ $\begin{array}{l}=12+7 \times(-4) \\ =-16 .\end{array}$
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