MCQ
Two coins are thrown simultaneously. The probability of getting no heads is:
  • A
    $\frac{1}{2}$
  • B
    $\frac{1}{3}$
  • $\frac{1}{4}$
  • D
    None

Answer

Correct option: C.
$\frac{1}{4}$
(c) $\frac{1}{4}$
Explanation:
Total sample space $=\{ HH , HT , TH , TT \}$
$n(S)=4$
Total favourable outcomes $=\{ TT \}$
$n(E)=1$
$\begin{array}{l}\therefore P(E)=\frac{n(E)}{n(S)} \\
=\frac{1}{4} .\end{array}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free