MCQ
The ability to form complex compounds by the transitional metal ion is due to
- ASmall size
- BVacant $'d'$ orbitals
- CHigh nuclear charge
- ✓All of these
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$\begin{align}
\begin{matrix}
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O\,\,\,\,\,\,\,O \\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||\,\,\,\,\,\,\,\,\,|| \\
H-O-C-C- \\
\end{matrix}\begin{matrix}
O\,\, \\
||\,\,\, \\
C{{H}_{2}}-C-O-H \\
\end{matrix} \\
p{{K}_{a}}=2.2\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,p{{K}_{a}}=3.98 \\
\end{align}$

Total no. of elimination products are (includes stereoisomers)
