The acceleration $a$ of a particle undergoing $S.H.M.$ is shown in the figure. Which of the labelled points corresponds to the particle being at -$x_{max}$
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(d) Using acceleration $A = - \,{\omega ^2}x$
$At - {x_{\max }}$ $A$ will be maximum and positive.
$At - {x_{\max }}$ $A$ will be maximum and positive.
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