The acceleration of a particle performing S.H.M. is at a distance of $3\; cm$ from the mean position is $ 12\,cm/sec^2 $. Its time period is ..... $\sec$
A$0.5$
B$1$
C$2$
D$3.14$
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D$3.14$
d (d)$T = 2\pi \sqrt {\frac{{{\rm{Displacement}}}}{{{\rm{Acceleration}}}}} $
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