MCQ
The active mass of $64\, gm$ of $HI$ in a two litre flask would be
- A$2$
- B$1$
- C$5$
- ✓$0.25$
✓
Answer
Correct option: D.
$0.25$
(d) $[HI] = \frac{{64\,gm}}{{128 \times 2\,litre}} = 0.25$
Active mass is the concentration in moles/litre.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
The dehydration of malonic acid $CH_2(COOH)_2$ with $P_4O_{10}$ gives:
→Choose the correct sequence for the geometry of the given molecules Borazone, Borazole, $B_3O_6^{-3}$ , $Fe_2Cl_6$, trimer of $FCN$. [$'P'$ stands for planar and $'NP'$ stands for non-planar]
→The $IUPAC$ name of the compound is
→State the electronic configuration for Nitrogen $\ce{[p = 7, n = 7].}$
→The $\ce{C−C}$ bond length of the following molecules is in the order :
→‘Lead pencil’ contains
The number of significant figures in $6.02 \times {10^{23}}$ is
→Correct statement is
The volume of a gas decreases from $500\,cc$ to $300\,cc$ when a sample of gas is compressed by an average pressure of $0.6 \,atm. $ During this process $10 \,J $ of heat is liberated. The change in internal energy is......$J$
→The increasing order of electron affinity of the electronic configurations of element is
$(I)\,1s^2\,2s^2\,2p^6 \,3s^2\,3p^5$ $(II)\, 1s^2\, 2s^2\, 2p^3$
$(III)\, 1s^2\, 2s^2\,2p^5$ $(IV)\, 1s^2\, 2s^2\,2p^6 \,3s^1$
→$(I)\,1s^2\,2s^2\,2p^6 \,3s^2\,3p^5$ $(II)\, 1s^2\, 2s^2\, 2p^3$
$(III)\, 1s^2\, 2s^2\,2p^5$ $(IV)\, 1s^2\, 2s^2\,2p^6 \,3s^1$