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Answer
Correct option: C.${(C{H_3})_2}C = C{(C{H_3})_2}$
c
(c) $\begin{array}{*{20}{c}}
{C{H_3} - C = C - C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,|} \\
{\,\,\,\,\,C{H_3}\,\,\,C{H_3}}
\end{array}\xrightarrow[{(2)\,Zn/{H_2}O}]{{(1)\,{O_3}}}$ $\mathop {\begin{array}{*{20}{c}}
{C{H_3} - CO - OC - C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\
{\,\,\,C{H_3}\,\,\,\,\,C{H_3}}
\end{array}}\limits_{Acetone} $
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