Question
The amplification factor of a triode valve is $15$. If the grid voltage is changed by $0.3 \,volt$ the change in plate voltage in order to keep the plate current constant (in volt) is
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Answer
(c)$\mu = \frac{{\Delta {V_p}}}{{\Delta {V_g}}}$$ \Rightarrow \Delta {V_p} = \mu \Delta {V_g}$ $=15 × 0.3 = 4.5 \,volt.$
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