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PART - 2 CH - 13 Oscillations — Physics STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 SciencePhysicsPART - 2 CH - 13 Oscillations1 Mark
MCQ
The amplitude of simple harmonic motion starting from equilibrium position is 1.0 cm and period second instantaneous displacement (cm) will be
  • A
    $y=0.1 \sin \frac{2 \pi}{1.0} t$
  • ✓
    $y=1.0 \sin \frac{2 \pi}{0.1} t$
  • C
    $y=1.0 \sin \frac{2 \pi}{1.0} t$
  • D
    $y=0.1 \sin 2 \pi \times 0.1 t$
✓

Answer

Correct option: B.
$y=1.0 \sin \frac{2 \pi}{0.1} t$
(B)

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