MCQ
The angle between vectors $(\vec{M} \times \vec{N})$ and $(\bar{N} \times \vec{M})$ is ................
- A$0$
- B$60$
- C$90$
- ✓$180$
$\vec{M} \times \vec{N} \neq \vec{N} \times \vec{M}$
$\vec{M} \times \vec{N}$ is from $\vec{M}$ to $\vec{N}$
$\vec{N} \times \vec{M}$ is from $\vec{N}$ to $\vec{M}$
This means the two vectors are in opposite direction.
$\text { So, } \vec{M} \times \vec{N} =\vec{N} \times \vec{M}$
$=180^{\circ}$
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$1.$ The speed of the block when it reaches the point $Q$ is :
$(A)$ $5 \ ms ^{-1}$ $(B)$ $10 \ ms ^{-1}$$(C)$ $10 \sqrt{3} \ ms ^{-1}$ $(D)$ $20 \ ms ^{-1}$
$2.$ The magnitude of the normal reaction that acts on the block at the point $Q$ is :
$(A)$ $7.5 \ N$ $(B)$ $8.6 \ N$ $(C)$ $11.5 \ N$ $(D)$ $22.5 \ N$
Give the answer question $1$ and $2.$

