MCQ
The area of a triangle whose sides are 15cm, 8cm and 19cm is:
- A$19\sqrt{91}\text{cm}^2$
- B$6\sqrt{91}\text{cm}^2$
- C$10\sqrt{91}\text{cm}^2$
- D$8\sqrt{91}\text{cm}^2$
✓
Answer
- $6\sqrt{91}\text{cm}^2$
Solution:
$\text{s}=\frac{15+8+19}{2}=21\text{cm}$
Area of triangle $=\sqrt{\text{s}(\text{s-a})(\text{s-b})(\text{s-c})}$
$=\sqrt{21(21-15)(21-8)(21-19)}$
$=\sqrt{21\times6\times13\times2}$
$=6\sqrt{91}\text{sq}.\text{cm}.$
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