MCQ
The atomic number of the element unnilennium is
- A$119$
- B$108$
- C$102$
- ✓$109$
$un$ $nil$ $enn$
Hence correct name $\rightarrow$ unnilennium
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true about this mechanism
$(I)$ $\left[ {{{\left( {P{h_3}P} \right)}_2}PdC{l_2}PdC{l_2}} \right]$
$(II)$ $\left[ {NiBrCl\left( {en} \right)} \right]$
$(III)$ $N{a_4}\left[ {Fe{{\left( {CN} \right)}_5}NOS} \right]$
$(IV)$ $Cr{(CO)_3}{\left( {NO} \right)_2}$
$(I)$ - $(II)$ - $(III)$ - $(IV)$
| $H - H$ bond energy | $:\, 431.37 \,kJ\, mol^{-1}$ |
| $C= C$ bond energy | $:\, 606.10\, kJ \,mol^{-1}$ |
| $C - C$ bond energy | $:\, 336.49\, kJ\, mol^{-1}$ |
| $C - H$ bond energy | $:\, 410.50\, kJ\, mol^{-1}$ |
Enthalpy for the reaction,
$\begin{array}{*{20}{c}}
{H\,\,\,\,H} \\
{|\,\,\,\,\,\,\,\,|} \\
{C = C} \\
{|\,\,\,\,\,\,\,\,\,|} \\
{H\,\,\,\,H}
\end{array}\, + \,H - H\, \to \,\begin{array}{*{20}{c}}
{H\,\,\,\,H} \\
{|\,\,\,\,\,\,\,\,|} \\
{H - C - C - H} \\
{|\,\,\,\,\,\,\,\,\,|} \\
{H\,\,\,\,H}
\end{array}\,$
will be .............. $\mathrm{kJ \,mol}^{-1}$