MCQ
The solubility of $PbC{l_2}$ is
- A$\sqrt {{K_{sp}}} $
- B$^3\sqrt {{K_{sp}}} $
- ✓$^3\sqrt {\frac{{{K_{sp}}}}{4}} $
- D$\sqrt {8{K_{sp}}} $
✓
Answer
Correct option: C.
$^3\sqrt {\frac{{{K_{sp}}}}{4}} $
(c) $PbC{l_2} ⇌ \mathop {P{b^{2 + }}}\limits_{S\,\,} + \mathop {2C{l^ - }}\limits_{S\,\,} $
${K_{sp}}$ of $PbC{l_2} = [P{b^{2 + }}] \times {[C{l^ - }]^2}$ ;${K_{sp}} = S \times {(2S)^2}$
${K_{sp}} = S \times 4{S^2}$$ = 4{S^3}$; ${S^3} = \frac{{{K_{sp}}}}{4}$; $S = \sqrt[3]{{\frac{{{K_{sp}}}}{4}}}$
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