MCQ
The atomicity of phosphorus is $X$ and the $P\hat PP$ bond angle in the molecule is $Y.$ What are $X$ and $Y$
- A$X = 4, Y =$ ${90^o}$
- ✓$X = 4, Y =$ ${60^o}$
- C$X = 3, Y =$ ${120^o}$
- D$X = 2, Y =$ ${180^o}$

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| List $I$ Isomeric pairs | List $II$ Type of isomers |
| $A$ Propanamine and $N-$Methylethanamine | $I$ Metamers |
| $B$ Hexan$-2-$one and Hexan$-3-$one | $II$ Positional isomers |
| $C$ Ethanamide and Hydroxyethanimine | $III$ Functional isomers |
| $D$ $o-$nitrophenol and $p-$nitrophenol | $IV$ Tautomers |
Choose the correct answer from the options given below :-
$O(g) + e^- \to O^-(g); \Delta H = - 142 \,kJ \,mol^{-1}$
$O^-(g) + e \to O^{2-} (g); \Delta H = 844\, kJ \,mol^{-1}$
This is because