MCQ
The average power dissipation in a pure capacitance in ac circuit is
- A$\frac{1}{2}C{V^2}$
- B$C{V^2}$
- C$\frac{1}{4}C{V^2}$
- ✓Zero
✓
Answer
Correct option: D.
Zero
d
(d) Average power in ac circuits is given by $P = {V_{rms}}{i_{rms}}\cos \phi $
For pure capacitive circuit $\phi = {90^o}$ so $P = 0$
(d) Average power in ac circuits is given by $P = {V_{rms}}{i_{rms}}\cos \phi $
For pure capacitive circuit $\phi = {90^o}$ so $P = 0$
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