MCQ
The bob of a pendulum of length $1$ is pulled aside from its equilibrium position through an angle $\theta$ and then released. The bob will then pass through its equilibrium position with a speed $v,$ where $v$ equals:
- A$\sqrt{2\text{gl}(1-\sin\theta)}$
- B$\sqrt{2\text{g}(1-\cos\theta)}$
- ✓$\sqrt{2\text{gl}(1-\cos\theta)}$
- D$\sqrt{2\text{gl}(1+\sin\theta)}$
