MCQ
The correct formula of borax is
- A$Na_2[B_4O_4(OH)_3].9 H_2O$
- ✓$Na_2[B_4O_5(OH)_4].8 H_2O$
- C$Na_2[B_4O_6(OH)_5].7 H_2O$
- D$Na_2[B_4O_7(OH)_6].6 H_2O$
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$(I)$ Acid chloride $(II)$ Aldehyde
$(III)$ Ketone $(IV)$ Ester
Select the correct answer from the codes given below :
| $Cl_2(g) \rightarrow 2Cl(g),$ | $242.3\,kJ\,mol^{-1}$ |
| $I_2(g) \rightarrow 2I(g),$ | $151.0\,kJ\,mol^{-1}$ |
| $ICl(g) \rightarrow I(g)+Cl(g),$ | $211.3\,kJ\,mol^{-1}$ |
| $I_2(s) \rightarrow I_2(g),$ | $62.76\,kJ\,mol^{-1}$ |
Given that the standard states for iodine and chlorine are $I_2(s)$ and $Cl_2(g),$ the standard enthalpy of formation for $ICl(g)$ is : ............... $\mathrm{kJ\,mol}^{-1}$
Reason : There is delocalisation of electrons from filled $d$ orbitals into the empty orbitals on the $CO$ ligands.
[Given : Atomic mass of $H =1, C =12, N =14, O =16, S =32, Cl =35$ ]