Question
The bond order in ${N_2}$ molecule is
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Answer
The Bond order in ${N_2}$ molecule is 3, $N \equiv N$ Here, ${N_b} = 2 + 4 + 2 = 8$ and ${N_a} = 2$
${\rm{B}}{\rm{.O}}. = (\,8 - 2)/2 = 3.$
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