The bulk modulus of a liquid is $3 \times 10^{10}\, Nm ^{-2}$. The pressure required to reduce the volume of liquid by $2 \%$ is  ........ $\times 10^{8}\; Nm ^{-2}$
JEE MAIN 2022, Medium
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$B =3 \times 10^{10}$

$-\frac{\Delta V }{ V }=0.02$

$B =\frac{\Delta P }{-\frac{\Delta V }{ V }} \Rightarrow \Delta P =- B \left(\frac{\Delta V }{ V }\right)$

$=\left(3 \times 10^{10}\right)(0.02)$

$=6 \times 10^{8} N / m ^{2}$

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