$-\frac{\Delta V }{ V }=0.02$
$B =\frac{\Delta P }{-\frac{\Delta V }{ V }} \Rightarrow \Delta P =- B \left(\frac{\Delta V }{ V }\right)$
$=\left(3 \times 10^{10}\right)(0.02)$
$=6 \times 10^{8} N / m ^{2}$

|Take atmospheric pressure $=1.0 \times 10^5 \mathrm{~N} / \mathrm{m}^2$, density of water $=1000 \mathrm{~kg} / \mathrm{m}^3$ and $g=10 \mathrm{~m} / \mathrm{s}^2$. Neglect any effect of surface tension.]
Reason $(R):$ In any steady flow of an incompressible fluid, the volume flow rate of the fluid remains constant.
