MCQ
The capacitive reactance of $50\mu\text{F}$ capacitance at a frequency of 2 × 103Hz will be ____ $\Omega$
- A$\frac{2}{\pi}$
- B$\frac{3}{\pi}$
- C$\frac{4}{\pi}$
- D$\frac{5}{\pi}$
✓
Answer
- $\frac{5}{\pi}$
Explanation:
Capacitive reactance $=\frac{1}{\omega\text{c}}$
$=\frac{1}{2\pi\text{fc}}$
$=\frac{1}{2\pi2\times10^3\times50\times10^{-6}}$
$=\frac{5}{\pi}\Omega$
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