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STD 12 - 2. Electric potential and capacitance — NEET STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceNEETSTD 12 - 2. Electric potential and capacitance4 Marks
Question
The capacitor $'C'$ is initially uncharged.  Switch $S_1$ is closed for a long time while $S_2$ remains open. Now at $t = 0$ , $S_2$ is closed while $S_ 1$ is opened. All the batteries are ideal and connecting wires are resistanceless. Find $INCORRECT$ statement
✓

Answer

$\dot{\mathrm{i}}=\frac{\mathrm{E}}{5 \mathrm{R}}$

equation of charge of capacitor

$q = CE{e^{ - t/\tau }}$

$q = EC{e^{ - t/5RC}}$

at $\quad t = 5\,{\rm{RC}}\,\ell {\rm{n}}\,2$

$\mathrm{q}=\frac{\mathrm{EC}}{2}$

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