So, $P V^{\frac{5}{3}}=k$
where, $Y=\frac{5}{3}$
Total work done during process $1$ and $2$,
$W_a=\frac{P_t V_t-P_i V_i}{1-y}$
$\rightarrow W_a=\frac{132 \times 10^{-5} \times 8 \times 10^{-3}-10^5 \times 10-3}{1-5 / 3}$
$W_a=112.5 J$
In adiabatic process the internal energy of system $\triangle Q=0$
$\text { so, } \Delta U=-W \Rightarrow-112.5 J$
Total heat supply between 1 and 2
$q_1+q_2=\Delta U+P_i\left(V_f-V_i\right)$
$=-112.5+10^5(8-1) \times 10^{-3}$
$=587.5 J$


