A gas is enclosed in a cylinder with a movable frictionless piston. Its initikl thermodynamic state at pressure $P_i=10^5 \mathrm{~Pa}$ and volume $V_i=10^{-3} \mathrm{~m}^3$ chanıes to i final state at $P_f=(1 / 32) \times 10^5 \mathrm{~Pa}$ and $V_f=8 \times 10^{-3} \mathrm{~m}^3$ in an adiabatic quasi-static process, such that $P^3 V^5=$ constant. Consider another thermodynamic process that brings the system from the same initial state to the same final state in two steps: an isobaric expansion at $P$, followed by an isochoric (isovolumetric) process at volume $V_f$. The amount of heat supplied to the system in the two-step process is approximately
IIT 2016, Advanced
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In adiabatic process ideal gas equation: $PV ^{\vee}=$ Constant from given data, $P ^3 V^5=$ constant

So, $P V^{\frac{5}{3}}=k$

where, $Y=\frac{5}{3}$

Total work done during process $1$ and $2$,

$W_a=\frac{P_t V_t-P_i V_i}{1-y}$

$\rightarrow W_a=\frac{132 \times 10^{-5} \times 8 \times 10^{-3}-10^5 \times 10-3}{1-5 / 3}$

$W_a=112.5 J$

In adiabatic process the internal energy of system $\triangle Q=0$

$\text { so, } \Delta U=-W \Rightarrow-112.5 J$

Total heat supply between 1 and 2

$q_1+q_2=\Delta U+P_i\left(V_f-V_i\right)$

$=-112.5+10^5(8-1) \times 10^{-3}$

$=587.5 J$

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