The capacity of parallel plate condenser depends on
Easy
Download our app for free and get started
(d) $C = \frac{{K{\varepsilon _0}A}}{d}$
Download our app
and get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
A condenser of capacitance $10\,\mu F$ has been charged to $100\,volts$. It is now connected to another uncharged condenser in parallel. The common potential becomes $40\,volts$. The capacitance of another condenser is......$\mu F$
Two capacitors ${C_1} = 2\,\mu \,F$ and ${C_2}\, = \,6\,\mu \,F$ in series, are connected in parallel to a third capacitor ${C_3} = \,4\,\mu \,F$. This arrangement is then connected to a battery of $e.m.f.$ $=$ $2V$, as shown in the figure. How much energy is lost by the battery in charging the capacitors
The potential due to an electrostatic charge distribution is $V(r)=\frac{q e^{-\alpha e r}}{4 \pi \varepsilon_{0} r}$, where $\alpha$ is positive. The net charge within a sphere centred at the origin and of radius $1/ \alpha$ is
Three long concentric conducting cylindrical shells have radii $R, 2R$ and $2\sqrt 2 $ $ R$ . Inner and outer shells are connected to each other. The capacitance across middle and inner shells per unit length is:
A parallel plate capacitor is of area $6\, cm^2$ and a separation $3\, mm$. The gap is filled with three dielectric materials of equal thickness (see figure) with dielectric constants $K_1 = 10, K_2 = 12$ and $K_3 = 14$. The dielectric constant of a material which when fully inserted in above capacitor, gives same capacitance would be
Two parallel plate capacitor with different plate seperation but the same capacitance are connected in series to a battery. Both capacitors are filled with air. The quantity that is $NOT$ the same for both the capacitors when they are fully charged is