The charge on $4\, \mu F$ capacitor in the given circuit is .... in $\mu C$
Medium
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(b) Equivalent capacity between $A$ and $B$ $ = \frac{{6 \times 4}}{{10}} = 2.4\,\mu F$
Hence charge across $4\,µF$ (Since in series combination charge remains constant) or $6\, µF$ = $2.4 × 10$ = $24 \,µC$
Hence charge across $4\,µF$ (Since in series combination charge remains constant) or $6\, µF$ = $2.4 × 10$ = $24 \,µC$
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