MCQ
The circle $x^2+y^2-3 x-4 y+2=0$ cuts x-axis:
  • A
    (2, 0), (-3, 0)
  • B
    (3, 0), (4, 0)
  • C
    (1, 0), (-1, 0)
  • (1, 0), (2, 0)

Answer

Correct option: D.
(1, 0), (2, 0)
  1. (1, 0), (2, 0)
Solution:
$x^2+y^2-3 x-4 y+2=0$
$x \text {-axis will be cut when } y=0$
$\text { put } y=0$
$x^2-3 x+2=0$
$(x-2)(x-1)=0$
$x=1,2$
$\text { points }(1,0),(2,0)$

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