MCQ
The colour of $KMnO_4$ is due to
- ✓Charge transfer from ligand to metal
- BCharge transfer from metal to ligand
- C$d-d$ transition
- D$p-d$ transition
✓
Answer
Correct option: A.
Charge transfer from ligand to metal
a
The $M n$ atom in $K M n O_{4}$ has +7 oxidation state with electron configuration $[A r] 3 d^{0} 4 s^{0}$.
The $M n$ atom in $K M n O_{4}$ has +7 oxidation state with electron configuration $[A r] 3 d^{0} 4 s^{0}$.
since no unpaired electrons are present, $d-d$ transitions are not possible. The molecule should,
therefore, be colourless.
The colour of $K M n O_{4}$ is intense purple due to $L \rightarrow M$ (ligand to metal) charge transfer $2 p(L)$ of
O to $3 d ( M )$ of $Mn$.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Generally transition elements form coloured salts due to the presence of unpaired electrons. Which of the following compounds will be coloured in solid state?
Assertion : ter-Butyl methyl ether is not prepared by the reaction of ter-butyl bromide with sodium methoxide.
Reason : Sodium methoxide is a strong nucleophile
Reason : Sodium methoxide is a strong nucleophile
In which of the following reactions migration of alkyl group from carbon to oxygen is observed ?
The rate of vapourisation of water depends upon:
Among the following, the reaction that proceeds through an electrophilic substitution is
Which of the following order is correct regarding boiling point ?
The reaction of formation of phosgene from $CO$ and $Cl_2$ is $CO + Cl_2 \to COCl_2.$ The proposed mechanism is
→$(i)$ $C{l_2}\,\underset{{{k_2}}}{\overset{{{k_1}}}{\longleftrightarrow}}\,2Cl$
$(ii)$ $Cl + CO\,\underset{{{k_4}}}{\overset{{{k_3}}}{\longleftrightarrow}}\,COCl$
$(iii)$ $COCl\, + \,C{l_2}\,\,\xrightarrow{{{k_5}}}\,COC{l_2}\, + \,Cl$ (slow)
Find the correct expression of rate law
The major product ' $P$ ' for the following sequence of reactions is:
→The product formed in the reaction is
Arrange the following compound in decreasing order of reactivity towards nucleophilic addition reaction
→${\left( {I} \right)}$ ${{C_6}{H_5}COC{H_3}}$
${\left( {II} \right)}$ ${C{H_3}COC{H_3}}$
${\left( {III} \right)}$ ${C{H_3} - CHO}$