MCQ
The compound forms nitroso amines when the substituents are


- A${R_1} = C{H_3},\,{R_2} = {R_3} = H$
- B${R_1} = {R_2} = H,\,\,{R_3} = {C_2}{H_5}$
- ✓${R_1} = H,\,\,{R_2} = {R_3} = C{H_3}$
- D${R_1} = C{H_3},\,\,{R_2} = {C_2}{H_5},\,\,{R_3} = H$

Sec. amine reacts with Nitrous acid to form nitroso amine yellow liquid.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Product $(A)$ is
$C{H_3} - COOH\xrightarrow{{N{H_3}}}A\xrightarrow{\Delta }B\xrightarrow[{B{r_2}}]{{KOH}}C$
Atomic weight : $Fe =55.85 ; \mathrm{S}=32.0$ $\mathrm{O}=16.00$
In the above reaction, the structural formula of $(A), "X"$ and $"Y"$ respectively are :