MCQ
The compound in which ${C^*}$ uses $s{p^3}$ hybrids for bond formation is
- A$H\mathop C\limits^ + OOH$
- B${(N{H_2})_2}\mathop C\limits^ + O$
- ✓${(N{H_3})_3}\mathop C\limits^ + OH$$HgC{l_2}$
- D$C{H_3}\mathop C\limits^ + HO$
Where as in $HC^*OOH,\left( NH _2\right)_2{ }C^*O$ and $CH _3 C^*HO$ in that all ${ }_{ C }^*$ having double bonds so the are showing $sp^2$ hybridization
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$O(g) + e^- \to O^-(g); \Delta H = - 142 \,kJ \,mol^{-1}$
$O^-(g) + e \to O^{2-} (g); \Delta H = 844\, kJ \,mol^{-1}$
This is because
$\Delta\text{S}(\text{C}\rightarrow\text{D})=30\text{ev},$
$\Delta\text{S}(\text{B}\rightarrow\text{D})=20\text{ev}$
$\text{A}\rightarrow\text{B}\\\downarrow\ \ \ \ \ \uparrow\\\text{C}\rightarrow\text{D}$
The entropy change for A → B would be:
$(A)$ Freezing of water to ice at $0^{\circ} C$
$(B)$ Freezing of water to ice at $-10^{\circ} C$
$(C)$ $N _{2}( g )+3 H _{2}( g ) \rightarrow 2 NH _{3}( g )$
$(D)$ Adsorption of $CO ( g )$ and lead surface
$(E)$ Dissolution of $NaCl$ in water