MCQ
The compound proposition $(p \wedge q) \rightarrow p$ is
- AA tautology
- BA contradiction
- CNeither (a) nor (b)
- DNone of these
| p | q | p^q | $(p \wedge q) \rightarrow p$ |
| T | T | T | T |
| T | F | F | T |
| F | T | F | T |
| F | F | F | T |
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
| X = k | 0 | 1 | 2 | 3 | 4 |
| P(X = k) | 0.1 | 0.4 | 0.3 | 0.2 | 0 |