Consider the following
$
C{H_3} - C{H_2} - N{H_2}$
$
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\rm{(I)}}
$
$
Ph - C{H_2} - N{H_2}$
$
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\rm{(II)}}
$
$
Ph - N{H_2}$
$
\,\,\,\,\,\,\,\,\,{\rm{(III)}}
$
Correct order of their basic strength is
→In the reaction $\begin{array}{*{20}{c}}
{\begin{array}{*{20}{c}}
{C{H_2}OH} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}} \\
{CHOH\,\,\,} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_2}OH}
\end{array}$ $+$ $\begin{array}{*{20}{c}}
{COOH} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{COOH}
\end{array}$ $\xrightarrow{{110\,{\,^o}C}}\,(A)$ product $(A)$ will be
→