MCQ
The compound which does not show paramagnetism is
- A$\left[ {Cu{{\left( {N{H_3}} \right)}_4}} \right]C{l_{_2}}$
- ✓$\left[ {Ag{{\left( {N{H_3}} \right)}_2}} \right]Cl$
- C$NO$
- D$N{O_2}$
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$ \mathrm{N}_2=3.0 \times 10^{-3} \mathrm{M}, \mathrm{O}_2=4.2 \times 10^{-3} \mathrm{M} \text { and } \mathrm{NO}=2.8 \times 10^{-3} \mathrm{M} . $
$ 2 \mathrm{NO}_{(\mathrm{g})} \rightleftharpoons \mathrm{N}_{2(\mathrm{~g})}+\mathrm{O}_{2(\mathrm{~g})}$
If $0.1 \mathrm{~mol} \mathrm{~L} \mathrm{~L}^{-1}$ of $\mathrm{NO}_{(\mathrm{g})}$ is taken in a closed vessel, what will be degree of dissociation ( $\alpha$ ) of $\mathrm{NO}_{(\mathrm{g})}$ at equilibrium?
[Given $\sqrt2 = 1.41$]