MCQ
The compound which shows metamerism is :
- A$\mathrm{C}_{5} \mathrm{H}_{12}$
- B$\mathrm{C}_{3} \mathrm{H}_{8} \mathrm{O}$
- C$\mathrm{C}_{3} \mathrm{H}_{6} \mathrm{O}$
- ✓$\mathrm{C}_{4} \mathrm{H}_{10} \mathrm{O}$
✓
Answer
Correct option: D.
$\mathrm{C}_{4} \mathrm{H}_{10} \mathrm{O}$
d
$\mathrm{C}_{4} \mathrm{H}_{10} \mathrm{O}$
$\mathrm{C}_{4} \mathrm{H}_{10} \mathrm{O}$
This molecular formula is applicable for homologous series ether (-O-) a bivalent functional group and as we know ether with minimum four-C shows metamerism. $\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{O}-\mathrm{CH}_{2}-\mathrm{CH}_{3}\, \&\, \mathrm{CH}_{3}-\mathrm{O}-\mathrm{CH}_{2}-\mathrm{CH}_{2}-\mathrm{CH}_{3}$ are metamers.
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