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9. Hydricarbon — Chemistry STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceChemistry9. Hydricarbon1 Mark
MCQ
The compound $X\, (C_5H_8)$ reacts with ammonical $AgNO_3$ to give a white precipitate and reacts with excess of $KMnO_4$ to give the acid, $(CH_3)_2CH-COOH$, therefore $X$ is
  • A
    $CH_2=CH-CH=CH-CH_3$
  • B
    $C{H_3}{\left( {C{H_2}} \right)_2}C \equiv CH$
  • ✓
    ${\left( {C{H_3}} \right)_2}CHC \equiv CH$
  • D
    ${\left( {C{H_3}} \right)_2}C = C = C{H_2}$
✓

Answer

Correct option: C.
${\left( {C{H_3}} \right)_2}CHC \equiv CH$
c
It should be terminal alkyne as gives white ppt. with ammonical $AgNO_3$. Also see nature of alkyne chain in acid.

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