MCQ
The condition for obtaining secondary maxima in the diffraction pattern due to single slit is
  • A
    $a\,\sin \,\theta \, = \,n\lambda $
  • $a\,\sin \,\theta \, = \,(2n - 1)\frac{\lambda }{2}$
  • C
    $a\,\sin \,\theta \, = \,(2n - 1){\lambda }$
  • D
    $a\,\sin \,\theta \, =\,\frac{n\lambda }{2}$

Answer

Correct option: B.
$a\,\sin \,\theta \, = \,(2n - 1)\frac{\lambda }{2}$
b
In the diffraction pattern due to single slit, condition for secondary maxima is $a \sin \theta=(2 n-1) \frac{\lambda}{2}$ where $n=2,3,4, \dots$

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