MCQ
The correct formula of diammine dichlorodicyano chromate $(III)$ is
- A$[CrCl_2(CN)_2(NH_3)_2]^{+3}$
- B$[CrCl_2(CN)_2(NH_3)_2]^{-3}$
- C$[CrCl_2(CN)_2(NH_3)_2]$
- ✓$[CrCl_2(CN)_2(NH_3)_2]^-$
✓
Answer
Correct option: D.
$[CrCl_2(CN)_2(NH_3)_2]^-$
d
In $\left[ Co \left( NH _{3}\right)_{5} CO _{3}\right] ClO _{4}$, five ammonia ligands and one carbonate ligand is attached to the central cobalt atom. Hence, the coordination number is six.
Let $X$ be the oxidation number of cobalt. $X+(-2)+(-1)=0$ or $X=3 .$ Hence,
the oxidation number is 3 .
In $\left[ Co \left( NH _{3}\right)_{5} CO _{3}\right] ClO _{4}$, five ammonia ligands and one carbonate ligand is attached to the central cobalt atom. Hence, the coordination number is six.
Let $X$ be the oxidation number of cobalt. $X+(-2)+(-1)=0$ or $X=3 .$ Hence,
the oxidation number is 3 .
The outer electronic configuration of cobalt (atomic number 27 ) is $3 d^{7} 4 s^{2} .$ The outer electronic configuration of $Co ^{+3}$ will be $3 d^{6} 4 s^{0} .$ Thus it contains six d
electrons.
$\left[ Co \left( NH _{3}\right)_{5} CO _{3}\right] ClO _{4}$ is inner orbital or low spin complexes. all the electrons are paired due to $d^{2} s p^{3}$ hybridization of $C o^{+3}$ ion. Hence, the number of unpaired d electrons is zero.
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