MCQ
The correct order of decreasing ionic nature of lead dihalides is
  • $Pb{F_2} > PbC{l_2} > PbB{r_2} > Pb{I_2}$
  • B
    $Pb{F_2} > PbB{r_2} > PbC{l_2} > Pb{I_2}$
  • C
    $Pb{F_2} < PbC{l_2} > PbB{r_2} < Pb{I_2}$
  • D
    $Pb{I_2} < PbB{r_2} < PbC{l_2} < Pb{F_2}$

Answer

Correct option: A.
$Pb{F_2} > PbC{l_2} > PbB{r_2} > Pb{I_2}$
a
Larger anions are more easily deformed to produce covalent nature. Also note decreasing ionic nature and not increasing

$PbF _2\,<\, PbCl _2\,>\, PbBr _2\,<\, PbI _2$

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