MCQ
The correct order of $H - M - H$ bonds angle is
- A$NH_3 < PH_3 < SbH_3 < BiH_3$
- B$AsH_3 < SbH_3 < PH_3 < NH_3$
- C$NH_3 < PH_3 < BiH_3 < SbH_3$
- ✓$BiH_3 < SbH_3 < AsH_3 < PH_3$
✓
Answer
Correct option: D.
$BiH_3 < SbH_3 < AsH_3 < PH_3$
d
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Efficiency of the following cell is $84\%$ . $A\left( s \right) + {B^{2 + }}(aq.) \rightleftharpoons {A^{2 + }}(aq.) + B(s)$ ; $\Delta {H^o} = - 285\,kJ$ . Then the standard $EMF$ of the cell will be ........... $\mathrm{V}$
→Which of the carbon atoms present in the molecule given below are asymmetric?
Hexagonal close packing is found in crystal lattice of:
On hydrolysis of a "compound", two compounds are obtained. One of which on treatment with sodium nitrite and hydrochloric acid gives a product which does not respond to iodoform test. The second one reduces Tollens reagent and Fehling's solution. The "compound" is
In the process of vulcanization:
For the decomposition of azomethane. $CH _{3} N _{2} CH _{3}( g ) \rightarrow CH _{3} CH _{3}( g )+ N _{2}$ (g) a first order reaction, the variation in partial pressure with time at $600\,K$ is given as
→Among the following, cyclic species are :
$(I)$ $H_5P_3O_{10}$ $(II)$ $[B_3O_3(OH)_5]^{2-}$ $(III)$ $H_5P_5O_{15}$ $(IV)$ $P_3N_3Cl_6$
→$(I)$ $H_5P_3O_{10}$ $(II)$ $[B_3O_3(OH)_5]^{2-}$ $(III)$ $H_5P_5O_{15}$ $(IV)$ $P_3N_3Cl_6$
The strongest $CO$ bond is present in
→Identitiy the product
The compounds $\left[\mathrm{Co}\left(\mathrm{SO}_4\right)\left(\mathrm{NH}_3\right)_5\right] \mathrm{Br}$ and $\left[\mathrm{Co}\left(\mathrm{SO}_4\right)\left(\mathrm{NH}_3\right)_5\right] \mathrm{Cl}$ represent:
→