- A$OF_2 < ClO_2 < H_2O < Cl_2O$
- ✓$OF_2 < H_2O < Cl_2O < ClO_2$
- C$OF_2 < H_2O < ClO_2 < Cl_2O$
- D$ClO_2 < OF_2 < H_2O < Cl_2O$
. $OCl _2$ has unexpectedly greater angle due to bulky surrounding group $Cl$.
Angle of $OF _2$ is smaller than that of $H _2 O$ as bond angle is inversely to electronegativity.
All these are $sp ^3$ hybridized. And have $2$ lone pairs but $ClO _2$ has only $3$ free electrons. Therefore, has highest bond angle.
Therefore, the bond angle order is: $ClO _2\,>\, OCl _2\, >\, H _2 O \, >\, OF _2$.
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$(A)$ All are isoelectronic
$(B)$ All have the same nuclear charge
$(C)$ $\mathrm{O}^{2-}$ has the largest ionic radii
$(D)$ $\mathrm{Mg}^{2+}$ has the smallest ionic radii
Choose the most appropriate answer from the options given below :


$I$. Boron trioxide is acidic
$II$. Oxides of aluminium and gallium are amphoteric
$III$. Oxides of indium and thallium are basic