MCQ
The correct order of strength of $H-$ bond in the following compound
  • A
    $H_2O > H_2O_2 > HF > H_2S$
  • B
    $HF > H_2O_2 > H_2O > H_2S$
  • C
    $HF > H_2O > H_2S > H_2O_2$
  • D
    $HF > H_2O > H_2O_2 > H_2S$

Answer

$(d)$ Strength of $H-$ bonding is higher in $H_2O$, than $H_2O_2$ because  the amount of formal negative charge on oxygen atom in case of water is more  than that of $H_2O_2$.

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