MCQ
The hydrogen ion concentration in a given solution is $6 \times {10^{ - 4}}.$ Its $pH$ will be
- A$6$
- B$4$
- ✓$3.22$
- D$2$
$pH = - \log \,\,[{H^ + }]$ $ = - \log \,\,[6 \times {10^{ - 4}}] = 3.22$.
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$(I)\, s-$ orbital of $A$ and $P_x$ -orbital of $B$
$(II)\, s-$ orbital of $A$ and $P_z$ orbital of $B$
$(Ill)\, p_y$ -orbital of $A$ and $p_z$ orbital of $B$
$(IV)\, s-$ orbital of both $(A)$ and $(B)$