MCQ
The correct order regarding the electronegativity of hybrid orbitals of carbon is
- A$sp < sp^2 < sp^3$
- B$sp > sp^2 < sp^3$
- ✓$sp > sp^2 > sp^3$
- D$sp < sp^2 > sp^3$
✓
Answer
Correct option: C.
$sp > sp^2 > sp^3$
c
The correct order regarding the electronegativity of hybrid orbitals of carbon is $sp >s p^{2}>s p^{3}$ because in $sp, sp^{2}$ and $s p^{3}$ hybrid orbitals s-orbital character is $50 \%, 33.3 \%$ and $25 \%$ respectively and due to higher s-character electron attracting tendency, i.e. electronegativity increases.
The correct order regarding the electronegativity of hybrid orbitals of carbon is $sp >s p^{2}>s p^{3}$ because in $sp, sp^{2}$ and $s p^{3}$ hybrid orbitals s-orbital character is $50 \%, 33.3 \%$ and $25 \%$ respectively and due to higher s-character electron attracting tendency, i.e. electronegativity increases.
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