Question
The correct representation of $\ce{CuSO_{4​}⋅5H_2​O}$ is:

Answer

For,$\ce{CuSO_4​.5H_2​O}$ in this $4H_2​O$ are bonded by co$-$ordinate bond and $1H_{2​}O$ by covalent bonding.
Therefore, Its formula of the compound is $\ce{[Cu(H_2​O)_4​]SO_4​⋅H_2​O}.$

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