MCQ
The correct representation of $\mathrm{CuSO}_4 \cdot 5 \mathrm{H}_2 \mathrm{O}$ is:
  • A
    $ {\left[\mathrm{Cu}\left(\mathrm{H}_2 \mathrm{O}\right)_5\right] \mathrm{SO}_4} $
  • B
    $ {\left[\mathrm{Cu}\left(\mathrm{H}_2 \mathrm{O}\right)_3 \mathrm{SO}_4\right] \cdot 2 \mathrm{H}_2 \mathrm{O}} $
  • C
    $ {\left[\mathrm{CuSO}_4 \cdot \mathrm{H}_2 \mathrm{O}\right] \cdot 4 \mathrm{H}_2 \mathrm{O}} $
  • $ {\left[\mathrm{Cu}\left(\mathrm{H}_2 \mathrm{O}\right)_4\right] \mathrm{SO}_4 \cdot \mathrm{H}_2 \mathrm{O}} $

Answer

Correct option: D.
$ {\left[\mathrm{Cu}\left(\mathrm{H}_2 \mathrm{O}\right)_4\right] \mathrm{SO}_4 \cdot \mathrm{H}_2 \mathrm{O}} $
For,
$\mathrm{CuSO}_4 \cdot 5 \mathrm{H}_2 \mathrm{O}$ in this $4 \mathrm{H}_2 \mathrm{O}$ are bonded by co$-$ordinate bond and $1 \mathrm{H}_2 \mathrm{O}$ by covalent bonding.
Therefore,
Its formula of the compound is $\left[\mathrm{Cu}\left(\mathrm{H}_2 \mathrm{O}\right)_4\right] \mathrm{SO}_4 \cdot \mathrm{H}_2 \mathrm{O}$.

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