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2. Electrochemistry — Chemistry STD 12 Science — Question

CBSE BoardEnglish MediumSTD 12 ScienceChemistry2. Electrochemistry1 Mark
MCQ
The correct representation of Nernst's equation is
  • ✓
    ${E_{{M^{n + }}/M}} = {E^o}_{{M^{n + }}/M} + \frac{{0.0591}}{n}\log \,({M^{n + }})$
  • B
    ${E_{{M^{n + }}/M}} = {E^o}_{{M^{n + }}/M} - \frac{{0.0591}}{n}\log \,({M^{n + }})$
  • C
    ${E_{{M^{n + }}/M}} = {E^o}_{{M^{n + }}/M} + \frac{n}{{0.0591}}\log \,({M^{n + }})$
  • D
    None of the above
✓

Answer

Correct option: A.
${E_{{M^{n + }}/M}} = {E^o}_{{M^{n + }}/M} + \frac{{0.0591}}{n}\log \,({M^{n + }})$
a
(a)$E = {E^o} - \frac{{RT}}{{nF}}\ln \frac{1}{{[{M^{n + }}]}}$;  $E = {E^o} + \frac{{RT}}{{nF}}\ln [{M^{n + }}]$

$E = {E^o} + \frac{{2.303RT}}{{nF}}\log [{M^{n + }}]$

Substituting the value of $ R, T (298\,K) $ and $F $ we get

$E = {E^o} + \frac{{0.0591}}{n}\log ({M^{n + }})$.

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