MCQ
The current density is a solid cylindrical wire of radius $R ,$ as a function of radial distance $r$ is given by $J ( r )= J _{0}\left(1-\frac{ r }{ R }\right) .$ The total current in the radial region $r =0$ to $r =\frac{ R }{4}$ will be
- A$\frac{5 J _{0} \pi R ^{2}}{32}$
- ✓$\frac{5 J _{0} \pi R ^{2}}{96}$
- C$\frac{3 J _{0} \pi R ^{2}}{64}$
- D$\frac{ J _{0} \pi R ^{2}}{128}$
