MCQ
The current $I$ drawn from the $5$ volt source will be ............... $A$


- A$0.17$
- B$0.33$
- ✓$0.5$
- D$0.67$

$R_{e q}=\frac{15 \times 30}{15+30}=10 \Omega \Rightarrow I=\frac{V}{R}=\frac{5}{10}=0.5 \mathrm{A}$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
