The current in a wire varies with time according to relation $I = 4 + 2t$. The quantity of charge which has passed through a crosssectionn of the wire during the time $t = 2\, s$ to $t = 6\, s$ will be .............. $\mathrm{C}$
A$24$
B$48$
C$36$
D$60$
Medium
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B$48$
b $\mathrm{q}=\int_{2}^{6}(4+2 \mathrm{t}) \mathrm{dt}=48 \mathrm{\,C}$
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Two wires of same metal have the same length but their cross-sections are in the ratio $3:1$. They are joined in series. The resistance of the thicker wire is $10\,\Omega $. The total resistance of the combination will be ............. $\Omega$
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